SOLUTIONS TO PART PER MILLION QUESTIONS.

*SOLUTIONS TO THE PART PER MILLION QUESTIONS BELOW*

NOTE.

One of the simplest ways to convert a given concentration to part per million (ppm) is to convert the unit of the mass given to you to milligram(mg)

and

convert the unit of the volume given to you to Litres(L)

*After doing those two conversions, then find out the mass (in milligram) of that substance given to you that would be present if the volume becomes one litre (1L)*

Therefore, we say that, part per million concentration is the quantity of a substance in milligram contained in 1L or 1 dmΒ³ of the given solution.

πŸ‘‡πŸΎπŸ‘‡πŸΎπŸ‘‡πŸΎ

It means that

1mg/L is the same as 1ppm.

πŸ‘‡πŸΎπŸ‘‡πŸΎ

i.e 1mg/L = 1ppm

πŸ‘‡πŸΎπŸ‘‡πŸΎπŸ‘‡πŸΎπŸ‘‡πŸΎπŸ‘‡πŸΎ

SOLUTION 1.

Given mass = 483mg

We don’t need to convert this mass to milligram (mg) since it is already given in milligram.

Given volume = 1L

We don’t need to convert this volume to litre (L) since it already given in litre.

πŸ‘‡πŸΎπŸ‘‡πŸΎπŸ‘‡πŸΎπŸ‘‡πŸΎ
This means thatπŸ‘‡πŸΎ

1L contains 483mg

Since, the mass in milligram contained in 1L here is equal to 483mg,

Therefore we have it as 483mg/L

Which is the same as 483ppm.

Note thatπŸ‘‡πŸΎ

mg/L is same as ppm.

πŸ‘‡πŸΎ
Answer = 483ppm

Option πŸ‘‰πŸΎ B

SOLUTION 2.

Given mass = 2.03×10^-⁴kg

To covert from kilogram (kg) to milligram (mg), we multiply with one million (1,000,000)

ThereforeπŸ‘‡πŸΎ

Mass = 2.03×10^-⁴ x 1,000,000

Mass = 203mg

Given Volume = 480ml

To convert from millilitre (ml) to litre (L), we divide with 1,000

ThereforeπŸ‘‡πŸΎ

Volume = 480/1000

= 0.48L

πŸ‘‡πŸΎπŸ‘‡πŸΎπŸ‘‡πŸΎπŸ‘‡πŸΎ

This means thatπŸ‘‡πŸΎ

0.48L contains 203mg.

So,πŸ‘‰πŸΎ 1L will contain X

Finding the “X” value of X, we have πŸ‘‡πŸΎ

X = 203(1)/0.48

So, X = 422.92mg

Therefore we have it as 422.92mg/L

πŸ‘‡πŸΎπŸ‘‡πŸΎπŸ‘‡πŸΎπŸ‘‡πŸΎ

Answer = 422.92ppm

Option πŸ‘‰πŸΎ C

SOLUTION 3.

πŸ‘‡πŸΎπŸ‘‡πŸΎπŸ‘‡πŸΎπŸ‘‡πŸΎπŸ‘‡πŸΎ

Given mass = 162g

To covert from gram (g) to milligram (mg), we multiply with one thousand (1,000)

ThereforeπŸ‘‡πŸΎ

Mass = 162 x 1,000

Mass = 162,000mg

πŸ‘‡πŸΎπŸ‘‡πŸΎπŸ‘‡πŸΎπŸ‘‡πŸΎ

Given Volume = 7.3×10^-⁴mΒ³

To convert from metre cube (mΒ³) to litre (L), we multiply with 1,000

ThereforeπŸ‘‡πŸΎ

Volume = 7.3×20^-⁴ x 1000

= 0.73L

πŸ‘‡πŸΎπŸ‘‡πŸΎπŸ‘‡πŸΎπŸ‘‡πŸΎ

This means thatπŸ‘‡πŸΎ

0.73L contains 162,00)mg.

So,πŸ‘‰πŸΎ 1L will contain X

Finding the “X” value of X, we have πŸ‘‡πŸΎ

X = (162,000 x 1) / 0.73

So, X = 221,917.8mg

This means 221,917.8mg/L

πŸ‘‡πŸΎπŸ‘‡πŸΎπŸ‘‡πŸΎ

Answer = 221,917.8ppm

Option πŸ‘‰πŸΎ E

SOLUTION 4.

πŸ‘‡πŸΎπŸ‘‡πŸΎπŸ‘‡πŸΎπŸ‘‡πŸΎπŸ‘‡πŸΎ

Given mass = 8.01Ug

NOTE

Ug means πŸ‘‰πŸΎ microgram

To covert from microgram (Ug) to gram (g), we divide with one million or we multiply with ten raised to the power of minus six (10^-6)

ThereforeπŸ‘‡πŸΎ

Mass = 8.01×10^-6g

To convert from gram (g) to milligram (mg), we multiply with 1,000

Therefore, πŸ‘‡πŸΎ

Mass = 8.01×10^-6 x 1000

Mass = 0.00801mg

πŸ‘‡πŸΎπŸ‘‡πŸΎπŸ‘‡πŸΎπŸ‘‡πŸΎ

Given Volume = 0.005dmΒ³

Remember that dmΒ³ is the same as L

Therefore,πŸ‘‡πŸΎ

Given volume = 0.005L

πŸ‘‡πŸΎπŸ‘‡πŸΎπŸ‘‡πŸΎπŸ‘‡πŸΎ

This means thatπŸ‘‡πŸΎ

0.005L contains 0.00801mg.

So,πŸ‘‰πŸΎ 1L will contain X

Finding the “X” value of X, we have πŸ‘‡πŸΎ

X = (0.00801 x 1) / 0.005

So, X = 1.602mg

This means 1.602mg/L

πŸ‘‡πŸΎπŸ‘‡πŸΎπŸ‘‡πŸΎ

Answer = 1.602ppm

Option πŸ‘‰πŸΎ C

SOLUTION 5.

Given concentration = 0.0056Kg/0.001mΒ³

πŸ‘‡πŸΎπŸ‘‡πŸΎπŸ‘‡πŸΎπŸ‘‡πŸΎπŸ‘‡πŸΎ

Given mass = 0.0056kg

To covert from kilogram (kg) to milligram (mg), we multiply with one million (1,000,000)

ThereforeπŸ‘‡πŸΎ

Mass = 0.0056 x 1,000,000

Mass = 5600mg

πŸ‘‡πŸΎπŸ‘‡πŸΎπŸ‘‡πŸΎπŸ‘‡πŸΎ

Given Volume = 0.001mΒ³

To convert from metre cube (mΒ³) to litre (L), we multiply with 1,000

ThereforeπŸ‘‡πŸΎ

Volume = 0.001 x 1000

= 1L

πŸ‘‡πŸΎπŸ‘‡πŸΎπŸ‘‡πŸΎπŸ‘‡πŸΎ

This means thatπŸ‘‡πŸΎ

1L contains 5600mg

This means 5600mg/L

πŸ‘‡πŸΎπŸ‘‡πŸΎπŸ‘‡πŸΎ

Answer = 5600ppm

Option πŸ‘‰πŸΎ A

For enquiry, call πŸ‘‰πŸΎ 08068113736.

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Berry
Berry
January 18, 2021 10:37 pm

Thanks for the correction sir

Akagod
Akagod
January 19, 2021 12:12 am

Thanks man you’re really great

Chioma
Chioma
January 19, 2021 4:11 am

Thanks Sir, we’re grateful πŸ™

Xandra
January 20, 2021 9:32 am

Thank you sir

Onyeonoro Olivia
Onyeonoro Olivia
January 20, 2021 8:15 pm

Thankz sir

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