SOLUTION TO THE 19TH MAY 2020 QUIZ QUESTION BY CATALYST.

*SOLUTIONS TO THE MAY 19TH 2020 CATALYST ONLINE QUIZ QUESTIONS*…πŸ‘‡πŸΌπŸ‘‡πŸΌπŸ‘‡πŸΌ

πŸ‘‡πŸΌπŸ‘‡πŸΌπŸ‘‡πŸΌπŸ‘‡πŸΌ

NUMBER  ONE…πŸ‘‡πŸΌ

Another name for water (H2O) is hydrogen oxide

ANSWERπŸ‘‰πŸΌπŸ‘‰πŸΌ
The conjugate acid of water is H3O^+

πŸ‘‡πŸΌπŸ‘‡πŸΌπŸ‘‡πŸΌπŸ‘‡πŸΌ

NUMBER  TWO…πŸ‘‡πŸΌ

ANSWERπŸ‘‰πŸΌ πŸ‘‰πŸΌ water must be present.

πŸ‘‡πŸΌπŸ‘‡πŸΌπŸ‘‡πŸΌπŸ‘‡πŸΌ

NUMBER THREE…πŸ‘‡πŸΌ

ANSWERπŸ‘‰πŸΌπŸ‘‰πŸΌBRONSTED_LOWRY theory.

πŸ‘‡πŸΌπŸ‘‡πŸΌπŸ‘‡πŸΌπŸ‘‡πŸΌ

NUMBER  FOUR…πŸ‘‡πŸΌ

ANSWERπŸ‘‰πŸΌπŸ‘‰πŸΌ A supersaturated solution.

πŸ‘‡πŸΌπŸ‘‡πŸΌπŸ‘‡πŸΌπŸ‘‡πŸΌ

NUMBER FIVE…πŸ‘‡πŸΌ

The compound give is Al2O3.

First, we dissociate it (breaking it up)..πŸ‘‡πŸΌ

Al2O3 —> *2Al^Β³+*  + *3(O^²–)*

The product of the concentrations of the ions is equal to the Ksp.πŸ‘‡πŸΌπŸ‘‡πŸΌ

Ksp = [2Al^Β³+]Β²  x  [3O^²–]Β³

Now replace each ion with letter “S” which means solubility of the substance.

ThereforeπŸ‘‡πŸΌ

Ksp = [2S]Β² . [3S]Β³

Opening up the bracket, we haveπŸ‘‡πŸΌ

Ksp = 2Β².SΒ² . 3Β³. SΒ³

Ksp = 4 . SΒ² . 27 . SΒ³

Joining the like terms together, we haveπŸ‘‡πŸΌπŸ‘‡πŸΌπŸ‘‡πŸΌ

Ksp = (4 x 27) x (S^2+3)

Therefore…πŸ‘‡πŸΌπŸ‘‡πŸΌπŸ‘‡πŸΌ

Ksp = 108S^5

NOTE THAT…πŸ‘‡πŸΌ

Letter “S” stands for SOLUBILITY.

Then making solubility subject of formula, we have πŸ‘‡πŸΌ

S^5 = Ksp/108

Therefore,

S = fifth root of(Ksp/108)

Let’s now substitute the Ksp value given to us the questionπŸ‘‡πŸΌ

SOLUBILITY = fifth root of (8.83×10^³–/108)

SOLUBILITY = fifth root of(0.000082)

ThereforeπŸ‘‡πŸΌ

SOLUBILITY = 0.152βœ…

I AM THE CATALYST…+2348068113736.

Subscribe
Notify of
guest
2 Comments
Oldest
Newest Most Voted
Inline Feedbacks
View all comments
THE CATALYST
May 25, 2020 1:20 pm

Chat me up via whatsapp

Unknown
May 22, 2020 10:13 pm

Sir please,I don't understand how you multiplied the fifth root by 0.000082,I tried it but it didn't give me,0.152

2
0
Would love your thoughts, please comment.x
()
x