SOLUTION TO MOLARITY OF SALT PRODUCED IN A REACTION

HERE IS THE DETAILED SOLUTION.



QUESTION๐Ÿ‘‡๐Ÿผ๐Ÿ‘‡๐Ÿผ๐Ÿ‘‡๐Ÿผ


What is the molarity of the salt produced in the reaction of 200ml of 0.1M HCl with 100ml of 0.5M KOH ?






*SOLUTION*๐Ÿ‘‡๐Ÿผ๐Ÿ‘‡๐Ÿผ๐Ÿ‘‡๐Ÿผ๐Ÿ‘‡๐Ÿผ

THE REACTION FOR THE EQUATION๐Ÿ‘‡๐Ÿผ

HCl + KOH–> KCl+H20

The salt formed is KCl.

So we are looking for the molarity or concentration of KCl according to the question.

From the balanced equation, mole ratio of HCl : KOH : KCl๐Ÿ‘‰๐Ÿผ 1 : 1 : 1

This๐Ÿ‘†๐Ÿฝmeans that in the reaction between HCl and KOH, the moles of HCl and KOH to be mixed together should be equal amounts and the mole of the salt KCl they will form will still be equal to that same mole of each of HCl and KCl mixed in the reaction.

๐Ÿ‘‰๐ŸผHCl : KOH : KCl

๐Ÿ‘‰๐Ÿผ 1mol  :  1mol :  1mol

Remember, a certain quantity of HCl and a certain quantity of KOH were mixed together, and we are asked to find the molarity (concentration) of the salt(KCl) formed in the reaction.

REMEMBER๐Ÿ‘‡๐Ÿผ๐Ÿ‘‡๐Ÿผ๐Ÿ‘‡๐Ÿผ๐Ÿ‘‡๐Ÿผ

Molarity means Concentration

And we know tha๐Ÿ‘‡๐Ÿผ

๐Ÿ‘‰๐ŸผConc = mole/Vol

*Therefore*๐Ÿ‘‡๐Ÿผ

๐Ÿ‘‰๐ŸผMole= Conc x Vol

So, let us find out the mole of each of HCl and KOH that were mixed together in that reaction.

*FOR HCl*

Conc. = mole/ Vol

Conc = 0.1M

Vol = 200ml

Converting Volume to litre, we have๐Ÿ‘‡๐Ÿผ

= 200/1000

Vol = 0.2L

So,

mole = Conc x Vol

= 0.2ร—0.1= 0.02mol of HCl

*FOR KOH*

Conc. = mole/ Vol

Conc = 0.5M

Vol = 100ml

Converting Volume to litre, we have๐Ÿ‘‡๐Ÿผ

= 100/1000

Vol = 0.1L

So,

mole = Conc x Vol

= 0.5ร—0.1= 0.05mol of KOH.

It means that in the reaction, 0.02mol of HCl was mixed with 0.05mol of KOH, which is wrong because๐Ÿ‘‡๐Ÿผ

From the balanced equation, it should be๐Ÿ‘‡๐Ÿผ

1 : 1 : 1

1mol HCl will combine with 1mol KOH to produce 1mol KCl

So, it should be either 0.02mol of HCl to be mixed with 0.02mol of KOH

But in the reaction, 0.02mol HCl was mixed with 0.05mol KOH which is not balanced because the 0.05mol quantity of KOH that was added was in excess.

Therefore, in order to balance it, only 0.02 mol of KOH will react and not the 0.05mol that was added.

So, if 0.02mol HCl reacts with only 0.02mol KOH, therefore only 0.02 mol of the salt KCl will be produced.

Since we now know the mole of KCl formed and we know the Volume if it which is the volume of the products (total volume)๐Ÿ‘‡๐Ÿผ

We can now find the molarity of the salt KCl formed.

๐Ÿ‘‡๐Ÿผ๐Ÿ‘‡๐Ÿผ๐Ÿ‘‡๐Ÿผ๐Ÿ‘‡๐Ÿผ๐Ÿ‘‡๐Ÿผ๐Ÿ‘‡๐Ÿผ๐Ÿ‘‡

mole of KCl = 0.02mol

Vol of KCl formed = Total volume of HCl and KOH mixed together๐Ÿ‘‡๐Ÿผ๐Ÿ‘‡๐Ÿผ

 Total volume of products๐Ÿ‘‡๐Ÿผ

 = 200+100=300ml

Converting to litre, we have๐Ÿ‘‡๐Ÿผ

Total Vol = 200ml + 100ml

= 300ml

Converting the total volume to litre, we have๐Ÿ‘‡๐Ÿผ

 = 300/1000

= 0.3L

NOTE๐Ÿ‘‡๐Ÿผ

Conc = mole/Vol

Conc = Molarity

Molarity= mol/Vol

Conc = 0.02/0.3

THE CATALYST…08068113736.
= 0.0667M โœ…

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Ricky_rizz
May 19, 2020 12:10 pm

This understandable and explicit..

Unknown
May 15, 2020 6:05 am

Hmmm
I don't understand

THE CATALYST
May 14, 2020 1:18 pm

Chat me up

Unknown
May 14, 2020 11:20 am

Still can't understand the solving ๐Ÿ˜”๐Ÿ˜”๐Ÿ˜”

Kcee
May 12, 2020 10:13 pm

Awesome
Tactical tho

Tycoons wurld
May 12, 2020 5:46 pm

This type is the one futo usually set for its students!!

Uchenna Stephen
May 12, 2020 12:55 pm

This involves high level of Chemistry knowledge ๐Ÿคฃ๐Ÿคฃ๐Ÿคฃ๐Ÿคฃ๐Ÿคฃ

THE CATALYST
May 12, 2020 10:37 am

No

Unknown
May 12, 2020 9:25 am

Had it been the two moles are thesame,
Will u add them thesame way u added their volumes?

Unknown
May 12, 2020 7:53 am

Wow

Unknown
May 12, 2020 7:26 am

Wow.. thanks

Unknown
May 12, 2020 7:18 am

Wow this is tactical

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