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Unknown
May 19, 2020 6:24 pm

Thomas
C

Onyi
May 18, 2020 11:48 am

D

Onyi
May 18, 2020 11:48 am

D

Unknown
May 17, 2020 3:00 pm

0.83

THE CATALYST
May 16, 2020 10:38 pm

Benny, its 0.83g

Unknown
May 16, 2020 1:47 pm

Lady j
De and is D none

Unknown
May 14, 2020 11:38 pm

Josh

Ans= D
Mass of BaSO4 in grams = 0.932g
Molarity or concentration of BaSO4 = 0.043mol/L

Unknown
May 14, 2020 8:25 pm

Marycynthia
0.932 g of Baso4

Uchenna Stephen
May 14, 2020 8:20 pm

D. None

Unknown
May 14, 2020 5:21 pm

Orisakwe Emmanuel
Ans is None

Unknown
May 14, 2020 5:20 pm

Orisakwe Emmanuel

Equation for the reaction..

Bacl2+Na2SO4=Na2CL2 + BaSO4
Number of moles: 1 1 = 1 1
Mole ratio: 1:1:1:1

Number of moles formed in Bacl2 and NaSO4

For Bacl2

Mole=0.160mx0.025l
=4*10^-3
For NaSO4

Mole=0.068*0.055
=3.74*10^-3
Or 4*10^-3

In other words Bacl2 reacted with NaSO4 To form BaSO4

So mole of BaSO4= 4*10^-3
Grams that was formed in BaSO4…..

BaSO4 volume formed= total volume of Bacl2 + NaSO4
= 0.093
Conc= 4*10^-3/0.093
Ans= 0.043g

Anonymous Heymeka
May 14, 2020 5:15 pm

D

The answer is 0.934g of BaSo4

Unknown
May 14, 2020 4:46 pm

Daniel
C.0.87g of BaSO4

Unknown
May 14, 2020 4:32 pm

From Benitha..
D previous ans.I gave was wrong..
0.932g of Baso4 is correct..
D is d correct ans..

Unknown
May 14, 2020 4:11 pm

From Benitha
0.832g..
None

Unknown
May 14, 2020 3:42 pm

D None
Precious

Unknown
May 14, 2020 2:06 pm

0.87g

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